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πŸ€– GPT

Code Analyzer

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πŸ”₯ Introducing the Code Analyzer prompt! 🌟 Ideal for programmers and developers striving for flawless code! βœ… Fully customizable: Submit your code for in-depth analysis and enhancement. βœ… Good for using with GPT, and all third-party tools like Jasper.ai and Copy.ai πŸ’ͺ Elevate your code quality with expert analysis and tailored improvements!
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$6.99
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After purchasing, you will gain access to the prompt file which you can use with GPT or the app builder. You'll receive 20 free generation credits with this purchase. By purchasing this prompt, you agree to our terms of service.
11 months ago

Prompt Details

Model
Chat - GPT-4 (gpt-4)
Token size
94 ($0.00280 / call)
Example input
[code] - "def add(x, y): return x + y def subtract(x, y): return x - y def multiply(x, y): return x * y def divide(x, y): return x / y print("Welcome to MessyCalc - the messy calculator app!") print("Select operation:") print("1. Add") print("2. Subtract") print("3. Multiply") print("4. Divide") choice = input("Enter choice (1/2/3/4): ") num1 = float(input("Enter first number: ")) num2 = float(input("Enter second number: ")) if choice == '1': print(num1, "+", num2, "=", add(num1, num2)) elif choice == '2': print(num1, "-", num2, "=", subtract(num1, num2)) elif choice == '3': print(num1, "*", num2, "=", multiply(num1, num2)) elif choice == '4': if num2 != 0: print(num1, "/", num2, "=", divide(num1, num2)) else: print("Cannot divide by zero!") else: print("Invalid input") print("Thank you for using MessyCalc!")"
Example output
Observations: 1. Single Responsibility Principle: Each function currently does a single job, which is good. However, the main body of the code is cluttered and performs multiple tasks without clear separation. 2. Input Validation: There's no check to ensure that the user doesn't provide non-numeric values for num1 and num2. This can raise a ValueError. 3. Choice Validation: If a user inputs anything other than 1, 2, 3, or 4, it's considered invalid. But the prompt doesn't mention any boundaries or constraints on the input. 4. Division by Zero: There's a check for division by zero, which is good. However, it's placed within the branch for division, making the code slightly less readable. 5. Code Duplication: The logic for getting user input (operation choice, numbers) and the logic for performing and displaying the calculation results are all mixed together. This can be modularized to improve readability and maintainability. 6. String Concatenation: Using commas to concatenate strings and variables in the print statement works but is not the most readable or efficient. Using f-strings or the format method might be clearer. Recommendations: 1. Separate Functions: Break the main code into separate functions like get_user_input(), perform_calculation(), and display_result(). 2. Handle ValueErrors: Wrap the input parsing with try-except to handle any potential errors gracefully. 3. Enhance Choice Prompt: Make it clear to the user what values they are expected to input. 4. Use a Dictionary for Operations: Instead of multiple if-elif statements, use a dictionary to map the choice to the respective function. 5. Use f-strings: Improve string concatenation using f-strings for better readability. 6. Enhance Input Loop: It would be user-friendly if the user is looped back to the main menu when they enter an invalid choice, rather than ending the program. Improved Code: def add(x, y): return x + y def subtract(x, y): return x - y def multiply(x, y): return x * y def divide(x, y): if y == 0: return "Cannot divide by zero!" return x / y def get_user_input(): print("Select operation:") print("1. Add") print("2. Subtract") print("3. Multiply") print("4. Divide") choice = input("Enter choice (1/2/3/4): ") try: num1 = float(input("Enter first number: ")) num2 = float(input("Enter second number: ")) return choice, num1, num2 except ValueError: return None, None, None def perform_calculation(choice, num1, num2): operations = { '1': add, '2': subtract, '3': multiply, '4': divide } operation = operations.get(choice) if operation: return operation(num1, num2) return "Invalid input" def main(): print("Welcome to ImprovedCalc - the not-so-messy calculator app!") while True: choice, num1, num2 = get_user_input() if choice is None: print("Invalid input. Please enter numbers.") continue result = perform_calculation(choice, num1, num2) if choice in ['1', '2', '3', '4']: symbols = ['+', '-', '*', '/'] print(f"{num1} {symbols[int(choice)-1]} {num2} = {result}") else: print(result) continue_calc = input("Do you want to continue? (yes/no): ") if continue_calc.lower() != "yes": break print("Thank you for using ImprovedCalc!") if __name__ == "__main__": main() This version is more modular, handles errors better, and improves user experience with the looped input system.
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