Codegenius C

Certainly! I can modify this code to include more operator options while maintaining its functionality. Here's the modified code: #include <iostream> using namespace std; int main() { char op; float num1, num2; cout << "Enter operator: +, -, *, /, %, ^: "; cin >> op; cout << "Enter two operands: "; cin >> num1 >> num2; switch(op) { case '+': cout << num1 << " + " << num2 << " = " << num1 + num2; break; case '-': cout << num1 << " - " << num2 << " = " << num1 - num2; break; case '*': cout << num1 << " * " << num2 << " = " << num1 * num2; break; case '/': if(num2 != 0) { cout << num1 << " / " << num2 << " = " << num1 / num2; } else { cout << "Error! Cannot divide by zero."; } break; case '%': if(num2 != 0) { cout << num1 << " % " << num2 << " = " << (int)num1 % (int)num2; } else { cout << "Error! Cannot divide by zero."; } break; case '^': cout << num1 << " ^ " << num2 << " = " << pow(num1, num2); break; default: // If the operator is other than +, -, *, /, %, or ^, error message is shown cout << "Error! Operator is not correct."; break; } return 0; } I have added two more operator options: the modulus operator % and the power operator ^. The modulus operator computes the remainder when num1 is divided by num2, while the power operator raises num1 to the power of num2. Note that I have also added some input validation to handle cases where num2 is zero, to avoid dividing by zero. The modulus operator also only works with integer operands, so I have cast num1 and num2 to integers using the (int) operator. I hope this helps! Let me know if you have any questions or need further assistance.